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+<WRAP left 40%>
+~~TOC~~
+</WRAP>
+//
+//
+<WRAP centeralign 100% bigger>
+<WRAP bigger fgred>Lab46 Tutorials</WRAP>
+<WRAP muchbigger>Special Products</WRAP>
+Shortcuts in Algebra
+</WRAP>
+<WRAP left 40%>
+<WRAP info bgwhite>
+The aim of this page is to explore numbers and the patterns they create.  The these examples demonstrate recognized methods of solving algebraic forms by manipulating the mathmatic order of precedence.
+The the expressed goal of this exploration is to build heavily on the concepts of multiplying and dividing binomials and to demonstrate basic mathematic algorithms that can be used to create workable solutions.
+</WRAP>
+</WRAP>
+<WRAP clear></WRAP>
+=====Distributive Law=====
+<WRAP indent fgred bigger>
+Rule:
+\\
+<latex>a(x-y)=ax-ay</latex>
+\\
+<latex>a(x+y)=ax+ay</latex>
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Derived
+</WRAP>
+The distributive property can be explained using small numbers.  Take for example, <latex>3 * 5 = 15</latex>.  Both 3 and 5 can be written different ways.  For example, 3 can be written as 2+1.  Thus, our equation could be written <latex>5 * (2+1)</latex> or <latex>5(2 + 1)</latex>.  In this case, the distributive property states that the value of ''a'', in this case 5 should be distributed to both terms inside the parenthesis.  Therefore, <latex>5(2 + 1)</latex> is equal to <latex>(5 * 2) + (5 * 1)</latex>
+  * 3 * 5 = 5(2+1) = (5 * 2) + (5 * 1) = 15
+\\
+<WRAP indent fgred bigger>
+Example:
+\\
+<latex>6(b-c)=6b-6c</latex>
+\\
+<latex>5a(a-4c)=5a^2-20ac</latex>
+</WRAP>
+=====FOIL=====
+<WRAP indent fgred bigger>
+The Rule
+  * <latex>(a+b)(c+d) = ac + ad + bc + bd</latex>
+</WRAP>
+<WRAP indent fgred bigger>
+Derived
+</WRAP>
+FOIL is a mnemonic used to describe the process of multiplying two binomials.  The process is as follows:
+  * First - The first two terms of the binomial are multiplied together
+  * Outside - The first term in the first binomial is multiplied by the second term in the second binomial
+  * Inside - The second term in the first binomial is multiplied by the first term in the second binomial
+  * Last - The second term in the first binomial is multiplied by the second term in the second binomial
+This concept is more plainly derived from real numbers.  Take this simple equation:
+  *<latex>6 * 8 = 48</latex>
+The above equation states that 6 repeated 8 times is 48.  However, 6 can also be written as 4+2, and the distributive law states that <latex>8(4+2)</latex> is equal to <latex>(8 * 4) + (8 * 2)</latex> which must also be equal to 48.
+  *<latex>6 * 8 = 8(4 + 2) = (8 * 4) + (8 * 2) = 48</latex>
+Building on this concept, 8 can also be represented in different ways.  8 could be written as 7+1.  So really, this example can be written in binomial notation:
+  * <latex>6 * 8 = (4 + 2)(7 + 1)</latex>
+This is where the above rule comes into play.  To multiply binomials, distribute each value across all other values.  The above binomial, "foiled" out looks like this:
+  * <latex>6 * 8 = (4 + 2)(7 + 1) = (4 * 7) + (4 * 1) + (2 * 7) + (2 * 1) = 48</latex>
+=====Difference of Squares=====
+<WRAP indent fgred bigger>
+Rule:
+\\
+<latex>(x+y)(x-y)=x^2-y^2</latex>
+\\
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Derived
+\\
+<latex>(x+y)(x-y) = x^2 + xy -xy - y^2 = x^2-y^2</latex>
+\\
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Example:
+\\
+<latex>(T+6)(T-6) = T^2 - 6T + 6T - 36 = T^2 - 36</latex>
+\\
+<latex>(4x+5y)(4x-5y) = 16x^2 - 25y + 25y - 25y^2 = 16x^2 - 25y^2</latex>
+</WRAP>
+=====Perfect Square Binomial=====
+<WRAP indent fgred bigger>
+Rule:
+\\
+<latex>(x+y)^2=x^2+2xy+y^2</latex>
+\\
+<latex>(x-y)^2=x^2-2xy+y^2</latex>
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Example:
+\\
+<latex>(i+3)^2=i^2+6i+9</latex>
+\\
+<latex>(3y-5)^2 \to 9y^2-2(3y)(5)+25 \to 9y^2-30y+25</latex>
+</WRAP>
+=====Irregular Forms=====
+<WRAP indent fgred bigger>
+Rule:
+\\
+<latex>(x+a)(x+b)=x^2+x(a+b)+ab</latex>
+\\
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Example:
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Rule:
+\\
+<latex>(ax+b)(cx+d)=acx^2+(ad+bc)+bd</latex>
+\\
+</WRAP>
+\\
+<WRAP indent fgred bigger>
+Example:
+\\
+<latex>(30x+7y)(2x-9y) \to 600x^2+(270y+140y)x-63y^2 \to 600x^2-130xy-63y^2</latex>
+</WRAP>
+=====Prefect Cubes=====
+<latex>
+(x-y)^3=x^3-3ax^2+3a^2x-a^3
+</latex>
+=====Sum of Cubes=====
+<latex>x^3+y^3=(x+y)(x^2-xy+y^2)</latex>
+=====Difference of Cubes=====
+<latex>x^3-y^3=(x-y)(x^2+xy+y^2)</latex>
+=====Quick Reference=====
+<WRAP fgred bigger>
+Distributive Property
+  *<latex>a(x-y)=ax-ay</latex>
+  *<latex>a(x+y)=ax+ay</latex>
+FOIL
+  * <latex>(a+b)(c+d) = ac + ad + bc + bd</latex>
+Difference of Squares
+  *<latex>(x+y)(x-y)=x^2-y^2</latex>
+Perfect Square Binomial
+  *<latex>(x+y)^2=x^2+2xy+y^2</latex>
+  *<latex>(x-y)^2=x^2-2xy+y^2</latex>
+Perfect Cubes
+  *<latex>(x-y)^3=x^3-3ax^2+3a^2x-a^3</latex>
+Sum of Cubes
+  *<latex>x^3+y^3=(x+y)(x^2-xy+y^2)</latex>
+Difference of Cubes
+  *<latex>x^3-y^3=(x-y)(x^2+xy+y^2)</latex>
+Irregular Forms
+  *<latex>(x+a)(x+b)=x^2+x(a+b)+ab</latex>
+  *<latex>(ax+b)(cx+d)=acx^2+(ad+bc)+bd</latex>
+</WRAP>
+=====Useful Links=====
+  *[[http://oakroadsystems.com/math/sumsqr.htm|Factoring the Sum of Squares]]

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