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--- notes:data:fall2023:projects:ttb1 [2023/09/16 20:46] – [REMOVING A NODE FROM THE LIST] jwieland
+++ notes:data:fall2023:projects:ttb1 [2023/09/16 20:50] (current) – [REMOVING A NODE FROM THE LIST] jwieland
@@ Line 69: / Line 69: @@
 =====REMOVING A NODE FROM THE LIST=====
-One of the ways to delete a specific Node from a linked list is to create a function that searches for the node by its properties (e.g. x, and y) and then removes it. the psudo-code would look something like this.
+One of the ways to delete a specific Node from a linked list is to create a function that searches for the node by its properties (e.g. x, and y) and then removes it. The psudo-code would look something like this.
 <code c>
-  void deleteBrick(Brick** start-of-list, int x, int y) {
+  deleteNode(Node** start-of-list, int x, int y) {
-  Brick* current =*start-of-list;
+  Node* current =*start-of-list;
-  Brick* previous= NULL;
+  Node* previous= NULL;
   while(current!=NULL){
     if (current_node->x == x && current_node->y == y) {
       if(previous==NULL){
-        node we want to delete from the list is the first node in the list
+        //node we want to delete from the list is the first node in the list
         *start-of-list =current->next;
       } else{
-        set the previous node's pointer to the current node's pointer
+        //set the previous node's pointer to the current node's pointer
       }
       free(current)
@@ Line 92: / Line 92: @@
   }
 </code>
+In essence we are itterating through the different nodes, and checking if they are the node we want to delete. Make sure to have a catch case for the first node in the list.
 ====AT THE START OF LIST====

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