~~DISCUSSION|Math Discussion~~

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<WRAP bigger fgred>Lab46 Tutorials</WRAP>
<WRAP muchbigger>Exponents</WRAP>
Basic Rules & Properties
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<WRAP fgred bigger indent>Rule 1</WRAP>
<latex>a^na^m = a^{n+m}</latex>
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<WRAP fgred bigger indent>Rule 2</WRAP>
<latex>\frac{a^m}{a^n} = a^{m-n}</latex>
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<WRAP fgred bigger indent>Rule 3</WRAP>
<latex>a^{-n} = \frac{1}{a^n} = (\frac{1}{a})^n</latex>
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<WRAP fgred bigger indent>Rule 4</WRAP>
<latex>a^0 = 1,  a \neq 0</latex>
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<WRAP fgred bigger indent>Rule 5</WRAP>
<latex>(ab)^m = a^mb^m</latex>
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<WRAP fgred bigger indent>Rule 6</WRAP>
<latex>(a^m)^n = a^{mn}</latex>
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<WRAP fgred indent>Derived</WRAP>
Take a perfect square number, let's use nine.  Multiply the number by itself ( nine times is 81 ); this is written <latex>9*9=81</latex>.  9 times 9 can also be written as <latex>9^2=81</latex>, that is, 9 squared, or 9 raised to the second power.  Since the substitution property allows 9 to be to be written as <latex>3*3=9</latex>, the previous could be written as <latex>(3*3)^2=81</latex>.  That is, the product of 3 repeated 3 times, repeated another 9 (or <latex>3*3</latex>) times is 81.  3 times 3 can be written as <latex>3^2</latex>, therefore, <latex>(3^2)^2=81</latex>.  Written out long-hand, the product of 3 squared raised to the second power looks like this: <latex>(3*3)*(3*3)=81 \to (3*3)^2 \to 3^{2*2} \to 3^4</latex>.

  *<latex>9*9=81 \to 9^2=81 \to (3*3)^2=81 & \to (3^2)^2=81 \to 3^{2*2} = 81 \to 3^4 = 81</latex>

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<WRAP fgred bigger indent>Rule 7</WRAP>
<latex>(\frac{a}{b})^m = \frac{a^m}{b^m}</latex>
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<WRAP fgred bigger indent>Rule 8</WRAP>
<latex>|a^2| = |a|^2 = a^2</latex>
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<WRAP fgred bigger indent>Rule 9</WRAP>
<latex>\sqrt{a} = a^\frac{1}{2}</latex>
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<WRAP fgred bigger indent>Rule 10</WRAP>
<latex>\sqrt[n]{a} = a^\frac{1}{n}</latex>
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